Intermediate steps
(i) Metallic sodium into gaseous sodium atom
The energy required per mole of sodium is 'enthalpy of sublimation' which is represented by (
Hs). This step is energy consuming process.
(ii) Dissociation of chlorine molecule into chlorine atoms
The energy required per mole of chlorine is 'enthalpy of dissociation' represented by (
d)
(iii) Gaseous sodium atom into gaseous cation
The energy required in this process is called Ionization energy (IE).
(iv) Gaseous chlorine atom into gaseous anion
This step involves the release of energy referred as Electron Affinity (EA).
(v) Combination of oppositely charged gaseous ions to form solid crystal
This involves the release of energy referred as lattice energy (U).

The various energy changes in different steps are as shown:
Born Haber Cycle for NaCl
The sum of the energy changes taking place during various steps is equal to DHf i.e., heat of formation of NaCl(s) according to Hess' Law.
Various values for NaCl are as follows:
IE of sodium (IE) = 495.8 kJ mol-1
EA of chlorine (EA) = -349 kJ mol-1
Lattice energy of NaCl (U) = -769.8 kJ mol-1
Substituting these values in equation (v) we get

= 393.0 kJ mol-1
Applications of Born Haber Cycle
Lattice energy of ionic solids
Born Haber Cycle helps us to calculate the lattice energy of ionic solid, provided other thermodynamic data is known. For example, the lattice energy of magnesium fluoride (MgF2) can be calculated when the sublimation energy (S) of Mg = 146.4 kJ mol-1; IE1 and IE2 values of Mg=737 and 1449 kJ mol -1 respectively; Dissociation energy (D) of fluorine = 158.8 kJ mol -1; EA of fluorine = - 328 kJ mol -1 and DHf of MgF2 =- 1096.5 kJ mol 1. Born Haber Cycle for MgF2 is as shown:
Born Haber Cycle for MgF2
DHf = DHs + DHd + (IE1 + IE2) + 2 EA1+ U
U = DHf - DHs - DHd - (IE1 + IE2) - 2 EA1
= -1096.5 - 146.4 - 158.8 - (737 + 1449) - 2(-328)
= -2931.7 kJmol-1

Born Haber cycle can help us to calculate the values of DHf for unknown compounds. From the calculated values of DHf one can predict whether the compound is stable or not. If DHf value is negative, the compound is stable. If DHf is positive, the formation of compound is highly unfavourable. For example, to calculate the value of DHf for hypothetical compound ArCl the data given is: IE1 for Ar = 526.3 kJ mol-1, Dissociation energy of chlorine (D) = 243 kJ mol-1; EA of chlorine is - 349 kJ mol-1 ; Lattice energy (U) of ArCl(s) is - 703 kJ mol -1. In the cycle below:
Born Haber cycle for ArCl(s)


The + ve value of DHf indicates that net energy is required for this process. Hence, formation ArCl is energetically unfavourable.
Electron affinities
The Born Haber cycle can be used for the calculation of electron affinities of some elements that are otherwise very difficult to measure. Heat of formation of a compound may be expressed as:
S, DHf, D, and IE are experimentally determined and lattice energy, U may be calculated by using other equation (Born Lande equation). Using the above equation, electron affinity may be calculated.
Proton affinities
The Born Haber cycle can also be used to calculate the proton affinities (PA) of some bases. The proton affinity of a species X is defined as the energy released in the reaction:
To calculate the proton affinity of NH3 using Born Haber Cycle for the process,
The thermodynamic data is as:
DH = - 144.5 kJ mol-1; IE = 1312 kJ mol-1; EA = -349.0 kJ mol-1
DHd = 433.0 kJ mol-1; U = -649.0 kJ mol-1
Substituting the values,
PA = - 144.5 - (433.0) - (1313.0) - (-349.0) - (-649.0) = -891.5 kJ mol-1








