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The equilibrium constant of such a reaction is called hydrolysis constant.
Hydrolysis of anion (A-)Hydrolysis of cation (B+)
Relation of Hydrolysis Constant and Ka and Kb
Salt of weak acid and strong base
Here, the anion (A-) is a stronger base than OH-, hence it undergoes hydrolysis to give free OH- ions. Therefore the resulting solution will be basic in character having pH greater than 7. For example
Other examples of this type of salts are CH3COONa, Na2CO3, Na3PO4, etc.
The aqueous solution of a salt of weak acid and strong base is alkaline. For the general reaction:Hydrolysis constant
The hydrolysis constant may be written as:

Multiplying equation (i) and (ii) and dividing by equation (iii), we get
Degree of hydrolysis
If the original concentration of the salt in the solution is 'c' mol/litre and 'h' is the degree of hydrolysis at that concentration, then

| Intial concentration | c | 0 | 0 |
|---|---|---|---|
| Concentration at eqilibrium | c(1-h) | ch | ch |

If 'h' is very small as compared to 1, we can assume 1 - h
1.
Kh = ch2


pH of the hydrolysed salt solution [OH-] = ch


Now, pH = -log [H+]


Now, -log Kw = pKw - log Ka = pKa
Knowing the molar concentration 'c' of the solution, Ka and Kw, the pH of the solution can be calculated.





