It states that,
"In a solution of volatile components, the partial vapor pressure of a component at a given temperature is equal to the mole fraction of that component in the solution multiplied by the vapor pressure of that component in the pure state".Now, let us consider a mixture of two completely miscible volatile liquids A and B, having the mole fraction xA and xB. Suppose at a given temperature their partial vapor pressures are pA and pB and the vapor pressure in pure state are:
P = PA + PB
or P = PoA cA + PoB cB= PoA (1-cB) + PoB cB [because cA + cB = 1]
= PoA - PoA cB + PoB cBP = (PoB - PoA)cB + PoA
Similarly by putting cB = 1-cA the vapor pressure of the solutionP = (PoA - PoB)cA + PoB
fig 3.5
As the values of PoA and PoB are constants at a particular temperature, it reveals that total pressure is a linear function of cB or cA i.e. the plot of P versus cA or P versus cB should be a straight line. The variation of P with mole fraction is given by the solid line III in the graph. The solutions which obey Raoult's law are called ideal solutions. For such solutions, the vapor pressure of the solution always lies between the vapor pressure of the pure components.The vapor pressure of a solution containing non-volatile solute is directly proportional to the mole fraction of the solvent. That is because, there is no contribution towards the vapor pressure of the solution from non volatile component (PB = 0).

where K is proportionality constant,

In terms of symbols,
But xA + xB = 1
or xA = 1-xB ……(2)From equations (1) and (2)
Rearranging
In the above equation pAo- ps represents lowering of vapor pressure and
the mole fraction of the non-volatile solute in the solution.



