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| Some Properties of Definite Integrals |
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| Proof: |
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| LHS = F(a) - F(b) |
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| = - [F(b) - F(a)] |
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| 2) |
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| Proof: |
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| LHS = F(b) - F(a) +F(c) - F(b) |
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| = F(c) - F(a) |
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| Proof: |
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| RHS = F(b) - F(a) + F(c) - F(b) |
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| = F(c) - F(a) |
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| Proof: |
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| Put a + b - x = t |
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| -dx = dt |
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| when x = a, t = b |
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| x = b, t = a |
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| = LHS |
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| Put a - x = t |
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| -dx = dt |
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| When x = 0, t = a |
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| x = a, t = 0 |
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| = LHS |
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(5)  |
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| Proof: |
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| = I1 + I2 |
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| Let us evaluate I2 |
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| Let 2a - x = t |
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| When x = 0, t = 2a |
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| When x = a, t = a |
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| = L.H.S. |
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| Proof: |
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| Consider |
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| When f (x) = f (2a - x) |
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| Put 2a-x = t |
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| -dx = dt |
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| when x = a, t = a |
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| x = 2a, t = 0 |
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| When f (x) = -f (2a - x), proceeding as above |
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| This value will be equal to |
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| Proof: |
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| = I1 + I2 |
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| When f (x) = f (-x) |
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| Let -x =t, -dx = dt or dx = -dt |
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| When x = -a , t = a |
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| x = 0, t = 0 |
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| When f (x) = -f (-x), proceeding as above |
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| Let -x = t, -dx = dt or dx = -dt |
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| When x = -a, t = a |
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| x = 0, t = 0 |
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| \ I = I1 + I2 |
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| Example: |
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Evaluate  |
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| Solution: |
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