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The number of ways of selecting r things out of n dissimilar things is denoted by C(n, r) or nCr.
Example:
From a class of 32 students, 4 are to be chosen for a competition. In how many ways can this be done?
Suggested answer:
We are to select 4 students from 32. This selection can done in

Theorem:
The number of combinations of n dissimilar things, taken r at a time is 
Proof:
C(n,r) is the required combination by definition. Each of these combinations consists of a group of r dissimilar things, which can be arranged among themselves in P(r,r) = r! ways. But the number of permutations of n different things taken r at a time is P(n,r).

Corollary 1:
C(n,r) = C(n,n-r)
Proof:

Corollary 2:
C(n,0) = C(n,n) = 1
Proof:

Corollary 3:

Proof:
If r = s, there is nothing to prove.
Now,




Corollary 4:

Proof:



Prove the following statements



Proof:




Difference between a Permutation and a Combination
i. In a combination, only selection is made. In a permutation, not only a selection is made, but also there is an arrangement of a definite order.
ii. There is no order of selection in combinations. In permutation, order is a must.iii. Usually (i.e., except in special cases or trivial cases), the number of permutations exceeds the number of combinations.

