Question 1
Question: In two right triangles, an acute angle and a side of one are equal to the the angle and corresponding side of the other. Prove that the triangles are congruent.

Answer: Given:
In triangles ABC and DEF,

BC = EF

To prove:

Proof:
In triangles ABC and DEF.

BC = EF ( given)


Question 2
Question: AB is a line segment AX and BY are two equal line segments drawn on opposite sides of line AB such that AX||BY. If line segment AB and XY intersect each other at the point P, then prove that

ii) a line segments AB and XY bisect each other at P.

Answer: Given:
AB is a line segment
AX||BY
AB and XY intersect at P
To prove:

ii) AP=PB and PY=PX
Proof:
Compare triangles APX and BPY,
(given)



AP = PB
( corresponding parts of congruent triangles)
PY = PX
Question 3
Question: 

Answer: Given:
AC=BC


To prove:

Proof:
In triangles DBC and EAC,
BC=AC (given)
(given)
From the figure,



From the figure,

From (i) and (ii),


Question 4
Question: In the adjoining figure, AB ^ BD, DE ^ BD, BC = CD and


Answer: Given:

BC=CD

To prove:

Proof:
Compare triangles ABC and ECD,
BC=CD ( given)
(given)
(given)

Question 5
Question: In the adjoining figure, AB||CD. BC and AD are transversals intersecting at O such that OA=OD. Show that 

Answer: Given:
AB||CD.
AD and BC intersect at O.
OA = OD.
To prove:

Proof:
In triangles AOB and COD,
OA=OD (given)
( alternate angles)
( vertically opposite angles)

Question 6
Question: In D PQR, P=40o, Q=65o and R=75o. Name the greatest side and the least side.
Answer: 
(theorem on inequalities)

(theorem on inequalities)
Question 7
Question: In D XYZ, XY=6.5cm, YZ=5.5cm and XZ=7.5cm. Name the greatest and smallest angle.
Answer: 
(theorem on inequalities)

(theorem on inequalities)
Question 8
Question: In the adjoining figure PQR is an equilateral triangle. N is any point on PQ. Show that (i) NR>PN (ii) NR>NQ.

Answer: Given:
In D PQR, PQ=PR=QR
To prove:
(i) NR>PN
(ii) NR>NQ
Proof:
In D PQR,
PQ=PR=QR ( given)
( Equilateral triangle is equiangular)
In D PNR,

(
is only a part of PRQ)
( given)
NR>PN (theorem on inequalities)
In DNQR,


NR>NQ (theorem on inequalities)
Question 9
Question: In a quadrilateral ABCD, AB=AD and BC>CD. Prove that
. (Hint: Join BD)

Answer: Given:

To prove:

Construction:
Join BD.
Proof:
In DBC,
BC>CD ( given)

...(i) (theorem on inequalities)
In D ABD, AB = AD ( given)

...(ii)
By adding (i) and (ii), we get



(adding equal thing to both sides
does not alter inequation)


Question 10
Question: In the adjoining figure D ABC, D is the mid point of BC and AD>BD or DC. Prove that
.

Answer: Given:
In D ABC, D is the mid-point of BC. AD>BD.
To prove:

Proof:
AD>BD ( given)

.....(i) (theorem on inequalities)
AD>DC ( given)

.....(ii) (theorem on inequalities)
By adding (i) and (ii), we get



