Parallelograms


   
 
Theorem 8
 
Statement
 
If there are three or more parallel lines and the intercepts made by them on one transversal are equal, the corresponding intercepts of any transversal are also equal.
 
 
Given:
 
l||m||n
 
P is a transversal intersecting l,m and n at A, B and C respectively such that AB=BC.
 
Q is another transversal drawn to cut l, m and n at D, E and F respectively. DE and EF are the intercepts made on q.
 
To prove:
 
DE = EF
 
Construction:
 
Draw a line through E parallel to p intersecting l in G, n in H respectively.
 
Proof:
 
 
AG||BE (given)
 
GE||AB (by construction)
 
AGEB is a parallelogram
 
 
But AB=BC (given)
 
From (i) and (ii), GE=EH
 
Now compare triangles GED and EFH,
 
GE=EH (proved)
 
 
 
 
 
Hence the theorem is proved.
 
 
     
   
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