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| Introduction |
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| In the given triangle ABC,
ÐA = 90o. Squares BCDE, ABFG and ACKL are drawn on the sides of the triangle. |
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| area of square BCDE = BC2 |
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| area of square ABFG = AB2 |
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| area of square ACKL = AC2 |
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| Pythagoras' theorem states that, |
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| area of square BCDE = area of square ABFG + area of square ACKL |
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| BC2 = AB2 + AC2 |
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