Construction - 12

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To construct when , AC = 4 cm, BC = 4.8 cm, two sides and the angle opposite to one of them are given.

(1) Draw a straight line AX

(2) At A, Construct

(3) From A, cut off AC = 4 cm.

(4) From C, cut off CB = 4.8 cm, B lying on AX.

(5) Then DABC is the required triangle.