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| Construction - 12 |
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To construct when , AC = 4 cm, BC = 4.8 cm, two sides and the angle opposite to one of them are given. |
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| (1) Draw a straight line AX |
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(2) At A, Construct  |
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| (3) From A, cut off AC = 4 cm. |
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| (4) From C, cut off CB = 4.8 cm, B lying on AX. |
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| (5) Then DABC is the required triangle. |
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