when
, AC = 4 cm, BC = 4.8 cm, two sides and the angle opposite to one of them are given.

(1) Draw a straight line AX
(2) At A, Construct
(3) From A, cut off AC = 4 cm.
(4) From C, cut off CB = 4.8 cm, B lying on AX.(5) Then DABC is the required triangle.
