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| Construction - 14 |
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To construct a right angled DABC when hypotenuse AC = 4 cm and hypotenuse and one acute angle are given |
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| (1) Draw a straight line AC = 4cm. |
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| (2) Taking OC as diameter, draw a semi circle on AC. |
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(3) At A, construct meeting the semicircle at B. Join BC. |
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| (4) Then DABC is the required right angled triangle. |
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