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| Construction - 15 |
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| To construct a triangle when the sum of two sides, the remaining side and the angle between them are given (We assume that the given angle can be constructed with ruler and compass alone) |
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In  BC = 3.8 cm,  and AB + AC = 6.5 cm |
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(1) Draw BC = 3.8 cm and at B make  |
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| (2) With B as centre and radius 6.5 cm, cut BX at D. Join CD. |
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(3) Draw perpendicular bisector of CD to cut BD at A. Join AC. Then,  is the required triangle. |
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