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| To find the length of the perpendicular from the point (x1,y1) on the line xcos a + ysin a = p |
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| To find the length of the perpendicular from the point (x1,y1) on the line xcosa + ysina = p
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| Let AB represent the given line xcosa + ysina = p. |
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| Let N' (x1, y1) be the given point. |
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| Through N', draw B'N'A'|| BA, so that OM produced will meet B'A' at N. |
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| Then, MN = M'N' = p'. |
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| ON = OM + MN = p + p' |
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| \The equation of the line A'N'B' is xcosa + ysina = p + p' |
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| The point N'(x1, y1) lies on A'B'. |
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