Family of Straightlines - Test Questions


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Question 21

Question:   Find the equation of the line through the intersection of the lines
6x+5y=11, 8x-5y=3 and parallel to the line 3x - 2y + 12 = 0.

Answer:    The given lines are
6x + 5y = 11 ...(i)
8x - 5y = 3 ...(ii)
Solving for x and y, the coordinates of the point of intersection of the two lines are (1,1).
The slope of the line through (1,1) = Slope of line 3x - 2y + 12 = 0
\ The equation of the line which passes through (1, 1) and whose slope is 3/2 is



Question 22

Question:   Show that the points (1,4) and (-1,-2) lie on either side of line 4x + 5y + 10 = 0.

Answer:    Let d = distance between the line 4x + 5y + 10 = 0 and the point (1,4).

Let d' be the distance between the line 4x + 5y + 10 = 0 and the point (-1,-2).

Since d and d' are of the opposite signs, the points lie on the either side of the line.

Question 23

Question:   Find the distance of the line 24x + 7y + 12= 0 from the point (4,6).

Answer:    Line 24x + 7y + 12 = 0, point (4,6).



6 units (since distance cannot be negative)

Question 24

Question:   Find the distance between the following pairs of parallel lines.
i) 3x + 4y + 20 = 0, 6x + 8y + 45 =0
ii) 12x + 15y + 41 = 0, 4x + 5y + 41 = 0

Answer:    i) 3x + 4y + 20 = 0, 6x + 8y + 45 = 0
Two lines are 3x + 4y + 20 = 0 ...(i)

6x + 8y + 45 = 0 ...(ii)
Distance of (i) from the origin (0,0) is

Distance of (ii) from the origin (0,0) is

Distance between the lines is

ii) 12x + 15y + 41 = 0, 4x + 5y + 41 = 0
The lines are 12x + 15y + 41 = 0 ...(i)
4x + 5y + 41 = 0 ...(ii)
The distance of line (i) from (0,0) is

The distance of line (ii) from (0,0) is

Distance between the lines is

Question 25

Question:   Find the point of intersection of the lines



Answer:   
2x + 3y - 7 = 0
3x - 5y - 1 = 0



The point of intersection is (2,1).
ii) mx - y - c = 0
x - my + c = 0






Adding (i) and (ii), we get


Subtracting (ii) from (i), we get
2mx = 0
x = 0

Question 26

Question:   Find the centroid of the triangle whose sides are
x + y - 1 = 0, x - 3y + 3 = 0 and x - y - 1 = 0.

Answer:    Let AB represent the side x + y - 1 = 0 ...(i)
Let BC represent the side x - 3y + 3 = 0 ... (ii)
Let CA represent the side x - y - 1 = 0 ... (iii)
Solving (i) and (ii) for x and y, we get the coordinates of B, i.e., B(0,1).
Solving (ii) and (iii) , we get the coordinates of C, i.e., C(3,2).
Solving (iii) and (i), we get the coordinates of A, i.e., A(1,0).
The coordinates of the centroid of the triangle are



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