Question Answers on Geometric Triangles


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Question 11

Question:   The vertices of a triangle are (0,0), (a, b) and (b, -a), find the equation to the sides of the triangle.

Answer:    Let O (0,0), A (a, b) and B (b, -a) be the vertices of the triangle OAB.

ay = bx or bx - ay = 0
Equation of side OB is


by = -ax
ax + by = 0
Equation of the side AB is




Question 12

Question:   Find the equation of the line through A (3,0) and B (0, -3).

Answer:    Let P (x, y) be any point on the line joining A and B.
\ Equation of line is


Question 13

Question:   Reduce each of the following straight line equation to the slope-intercept form. Find m and c.



Answer:    The slope-intercept form of the equation of line is y = mx + c.










Question 14

Question:   Find the equation of the line through (1,2) and parallel to x + 3y = 1.

Answer:    Given line is x + 3y = 1.



The line passes through (1,2).
Let P (x, y) be any point on the required line.



Aliter:
The line parallel to x + 3y - 1 = 0 is x + 3y = k.
This line passes through (1,2).
Putting x = 1 and y = 2 in x + 3y = k, we have

The equation of the required line is x + 3y = 7.

Question 15

Question:   Find the equation of the line with y-intercept 7 and parallel to
4x + 5y = 8.

Answer:    Reduce the equation to y = mx + c form .



But c = 7,


Question 16

Question:   Find the value of 'a' for which the lines ax + 4y + 5 = 0 and 9x + ay - 4 = 0 are parallel to each other.

Answer:    ax + 4y + 5 = 0 and 9x + ay - 4 = 0 are parallel to each other, the slopes are equal.





Question 17

Question:   Find the equation of the line perpendicular to the line 8x + 5y = 7 and passing through (1, 2).

Answer:   

( Product of slopes of two perpendicular lines = -1)





Aliter:
Given line is 8x + 5y = 7.
The line perpendicular to 8x + 5y = 7 is 5x - 8y = k.
This line passes through (1,2).


The required equation of the line is
5x - 8y = -11 or 5x - 8y + 11 = 0

Question 18

Question:   Find the equation of the line, which bisects the line joining (3, -1) and (5,11) and also bisects the distance between the points (-5,2) and (9,6).

Answer:    The co-ordinates of the middle point of the line joining (3,-1) and (5,11) is

Let P (4,5) be the point.
The co-ordinates of the middle point of the line joining (-5,2) and (9, 6) is

Let Q (2,4) be the point.
We have to find the equation of the line joining the points P and Q.




Question 19

Question:  

Answer:   




\ The required equation is


Question 20

Question:   Find the image of the point (-1,1) w.r.t to the line 3x + 4y = 32.

Answer:   
Let the image of the point P (-1,1) about the line AB be Q (h,k).
PQ is perpendicular to AB and is bisected at C.









Solving (ii) and (i) for h and k, we have

Reflection of P (-1,1) about the line 3x + 4y = 32 is



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