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| Theorem |
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| Sum of the angles of a triangle is equal to two right angles. |
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| ABC is a triangle |
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 A +  B +  ACB = 180o |
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| Produce BC to D. Through C draw CE || BA. |
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| If one side of a triangle is produced, the exterior angle so formed is equal to the sum of the interior opposite angles. |
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In  ABC, BC is produced to D. |
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If in a triangle ABC, the bisectors of the angles ABC and ACB meet at M, prove that  |
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 (Sum of angles of a D = 180o) |
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Also  ( MB bisects  ) |
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 ( MC bisects  ) |
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 …(1) |
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In  |
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 (Sum of the angles of a  = 180o) |
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| Using (1) |
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 BMC = 180O - ( CBM +  BCM) |
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or  (Proved) |
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