
The restriction on x is not required when n is a natural number.
Now, we shall see that when n is a natural number, then the above expansion coincides with that as given earlier.Let n
N and |x|<1, then we have


This is the same expansion as would have given by the binomial theorem for positive integral index.
Some Observations:
- If n
N, then (1 + x)n is defined for all values of x and if n
Q - N, then (1 + x)n is defined only when |x|<1.
- If n
N, then (1 + x)n contains only n+1 terms and if n
Q - N, then (1 + x)n contains infinitely many terms.
- In the expansion of (1 + x)n, the exponent of x goes on increasing through 0.
- If n
N, then the coefficient of any term in (1 + x)n is nCk where k is the exponent of x.
- If n
N, then the exact value of (1 + x)n can be found by adding all terms (equal to n+1) in the expansion of (1 + x)n and if n
Q - N, then only an approximate value of (1 + x)n can be found by adding certain finite number of terms in the expansion of (1 + x)n.
Working rules for expanding (1 + x)n
n
Q:
Step 1: a)
If n
N, then (1 + x)n can be expanded for all values of x and has (n+1) terms.
b) If n
Q - N, then (1 + x)n can be expanded only when |x|<1 and has infinitely many terms.
Step 2:
The first term in (1 + x)n is always 1.
Step 3:
The second terms is the product 'nx' of n and x.
Step 4:
For the third term, take coefficient as
increase the power of x by 1. Thus, the third term is
Repeat this process repeatedly.
