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Case 1: n is even.
Let n = 2k
The number of terms is n+1 i.e., 2k+1.
The middle term has k terms before it.

Case 2: n is odd.
Let n = 2k+1
The number of terms is n+1 i.e., (2k + 1) + 1 = 2k + 2.
In this case, there are two middle terms and are after k terms.


Thus, in (a + b)n:

Note:
The middle terms may be easily found out by using the following method:
i) When n is even, we add the even number 2 to n and divide by 2 to get the middle term i.e.,
term.
ii) When n is odd, we add the odd numbers 1 and 3 to n and divide by 2 to get the middle terms i.e.,
terms.
Example:
Find the middle terms in the expansion of:

Suggested answer:








