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| Indices |
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| We know that 64 = 2 x 2 x 2 x 2 x 2 x 2 = 26 |
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| Here 2 is called the base and 6 is called the power (or index or exponent). |
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We say that "64 is equal to base 2 raised to the power 6". |
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Similarly, if m is a positive integer and |
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then a a a …m times = am. |
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If m and n are positive integers, and then |
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(i) am an = am + n [Product Law] |
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(ii) [Quotient Law] |
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| (iii) (am)n = amn [Power Law] |
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| (iv) (ab)m = am . bm |
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(v)  |
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| (vi) ao = 1 |
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(vii)  |
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An irrational root of a positive rational number is called a surd. Consider a number with base 'a' as a positive rational number with power of a fraction, say then |
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Since is an nth root, it is called a surd of order n, if it is irrational. |
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e.g., (i) is a surd of order 3. |
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(ii) is a surd of order 2. |
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(iii) is NOT a surd because and 3 is NOT an irrational number. |
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| Without using tables, simplify: |
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(i) 36-1/2 (ii)  |
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| (i) 36-1/2 |
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| = (62)-1/2 = 6-1 |
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(ii)  |
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Evaluate:  |
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Given expression  |
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| Simplify: |
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(i) |
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| (ii) If 2x+2 = 128, find the value of x. |
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(iii) Simplify: |
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(iv) Simplify:  |
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| (v) Show that (xp - q)p + q (xq - r)q + r (xr - s)r+s = 1 |
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(vi) 49 7x = (343)2x - 5 find 'x'. |
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(i) Given expression:  |
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(ii) Since 128 = 2 2 2 2 2 2 2 |
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| = 27 |
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We have 2x+2 = 27 [ bases are equal ] |
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x + 2 = 7 [ powers are equal ] |
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x = 5 |
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(iii)  |
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(iv)  |
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= (x3a y6)1/4 (x2/3 y-1)a  |
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= x3a/4 y3/2 x2a/3 y-a [ (x3a)1/4 = x3a/4 (power law)] |
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| (v) LHS = x(p - q) (p + q) x(q - r) (q + r) x(r - s) (r +s) |
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| = x0 = 1 = R.H.S |
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(vi) 49 7x = (343)2x - 5 |
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72 7x = (73)2x - 5 |
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72+x = 76x - 15 |
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| As the bases are equal, the powers are also equal. |
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2 + x = 6x - 15 |
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| or 5x = 17 |
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