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| Factorisation using Identities |
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| Recall the following identities for finding the products: |
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| Observe that the LHS in the identities are all factors and the RHS are their products. Thus, we can write the factors as follows: |
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| From the above identities we observe that a given expression, which is in the form of an identity can be written in terms of its factors. |
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| which can be reduced to this form. Let us consider some examples. |
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| Example 1: |
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| Suggested answer: |
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| Example 2: |
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| Suggested answer: |
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| Example 1: |
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| Suggested answer: |
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| Example 2: |
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| Suggested answer: |
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| Steps for factorisation using identities: |
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Recognise the appropriate identity. |
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Rewrite the given expression in the form of the identity. |
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Write the factors of the given expression using the identity. |
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| Example 1: |
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| Suggested answer: |
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| Example 2: |
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| Suggested answer: |
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| Example 1: |
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| Suggested answer: |
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| Example 2: |
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| Suggested answer: |
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| [Since both are same i.e., 4ab and 4bc are negative, b should be negative] |
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| Example 1: |
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| Suggested answer: |
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| Here we have x = 2x, y = 3y |
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| Example 2: |
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| Suggested answer: |
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| Example 3: |
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| Here x = 7, y = 2x |
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| Example 4: |
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| Suggested answer: |
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| Here x = 6a, y = 2b |
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| Let x + y = u |
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| Substitute x + y for u, |
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| Hence, |
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| Example 1: |
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| Suggested answer: |
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| Here x = 2a, y = b, z = 3c |
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| Example 2: |
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| Suggested answer: |
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| Here x = 2x, y = 5y, z = 1 |
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