When f(x) is divided by (x-a) the remainder is (x-a) and if the remainder f(a) = 0 then x - a is a factor of the expression f (x).

Remainder theorem
If f(x) is a polynomial in x and is divided by x-a; the remainder is the value of f(x) at x = a i.e., Remainder = f(a).
Proof:
Let p(x) be a polynomial divided by (x-a).Let q(x) be the quotient and R be the remainder.
By division algorithm,Dividend = (Divisor x quotient) + Remainder
p(x) = q(x) . (x-a) + RSubstitute x = a,
p(a) = q(a) (a-a) + Rp(a) = R (a - a = 0, 0 - q (a) = 0)
Hence Remainder = p(a).Example 1:
Find the remainder when 2x3+4 is divided by
a) x-1b) x-2
d) x+1
Suggested answer:
Let f(x) = 2x3 + 4
a) When f (x) is divided by x-1,R = f (1)
= 2(1)3+ 4= 6
b) When f (x) is divided by x-2,R = f (2)
= 2(2)3+ 4= 20

d) When f(x) is divided by x+1, i.e., x-(-1).
R = f(-1)= 2(-1)3 + 4
= -2+4 = 2Example 2:
Factorise x2 - 7x + 10.
Suggested answer:
Let f(x) = x2 - 7x + 10
Then f (2) = (2)2 - 7(2) +10 [By trial and error method]
To find the other factor of x2 - 7x + 10, divide x2 - 7x + 10 by (x-2)

Verification:

Example 3:
Factorise x2 + 3x -4 using Remainder theorem.
Suggested answer:
Let f(x) = x2 + 3x - 4
Step 1:
Find a value of the variable x for which the value of x2 + 3x - 4
is equal to 0.Let x =1,
Then, f(1) = (1)2 + 3(1) - 4 = 0
Step 2:
Divide x2 + 3x -4 by (x-1),

Step 3:


Example 4:
Factorise 2x3 + x2 - 2x - 1.
Suggested answer:
Let f (x) = 2x3 + x2 - 2x - 1
= 0
Now, divide 2x3 + x2 - 2x - 1 by (x-1),




Example 5:
Factorise completely 2x3 - 7x2 - 3x + 18.
Suggested answer:
Let f (x) = 2x3 - 7x2 - 3x + 18
Let x = 1,






Steps for factorisation using remainder theorem
- By trial and error method, find the factor of the constant for which the given expression becomes equal to zero.
- Divide the expression by the factor that is determined in step 1.
- Factorise the quotient. If the quotient is a trinomial, factorise it further.
- If the expression is a 4th degree expression, the first step will be to reduce this to a trinomial and then factorise this trinomial further.
