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Question 41
Question: If the pth, qth, rth, sth terms of an AP are in GP, show that
p - q, q - r, r - s are in GP.
Answer: Let a = first term and d = common difference of the AP.




Since ap, aq, ar, as are in GP, then



Question 42
Question: If p, q, r are in AP and x, y, z are in GP, then prove that 
Answer: 
Also q = p + d, r = p + 2d, where d is the common difference of the AP.
x, y, z are in GP. Let R be the common ratio



Question 43
Question: Find geometrically the GM between a and b?
Answer: Let G be the Geometric mean between a and b.

Geometrically, if AB = a, BC = b.
On a line ABC, draw a semi circle on AC, with AC as diameter. Draw BD perpendicular to AC at B to cut the semicircle at D.
Draw AD and CD.




BD is the GM between AB and BC.
Question 44
Question: Insert 3 GM's between 8 and 648.
Answer: a = 8, b = 648 R = Common ratio
Let the three GM be aR, aR2, aR3. then b = aR4

\ The three GM's are 8(3), 8(3)2, 8(3)3

Question 45
Question: If one arithmetic mean A and two geometric means g1, g2 be 
Answer: Let the two numbers be a and b.
If A is the AM between a and b then a, A, b are in AP.

If g1, g2 are the GM's between a and b then a, g1, g2, b are in GP.



Question 46
Question: If S1, S2, S3 be respectively the sum of n, 2n, 3n terms of GP, prove that:
i) S12+S22 = S1(S2 + S3)
ii) S1(S3 - S2) = (S2 - S1)2
Answer: 




















Question 47
Question: Find the sum of n terms of the series 5 + 55+ 555 + ...
Answer: 


Here a = 10, r = 10, n = n




Question 48
Question: If y = x + x2 + x3+ ... to infinite number of terms, then 
Answer: 


Question 49
Question: Insert
i. 2 Geometric means between 2 and 16

iii. 4 Geometric means between 5 and 0.00005
iv. 5 Geometric means between 3 and 192


Answer: 



























Question 50
Question: If the AM between two numbers exceeds their GM by 2 and the ratio of two numbers is 4, find the numbers.
Answer: Let the numbers be a and b (a > b)

A - G = 2 (by data)







