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| Multiplication Rule of Probability |
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| We have already proved that if two events A and B from a sample S of a random experiment are mutually exclusive, then |
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In this section, we examine whether such a rule exists, if ' ' is replaced by ' ' and '+' is replaced by 'x' in the above addition rule. If it does exist, what are the particular conditions restricted on the events A and B. |
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| This leads us to understand the dependency and independency of the events. |
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| Example: |
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| A bag contains 5 white and 8 black balls, 2 balls are drawn at random. Find |
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| a) The probability of getting both the balls white, when the first ball drawn, is replaced. |
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| b) The probability of getting both the balls white, when the first ball is not replaced. |
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| Suggested answer: |
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a) The probability of drawing a white
ball in the first draw is . Since the ball is replaced, the probability of getting white ball in the second
draw is also . |
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b) The probability of drawing a white
ball in the first draw is . If
the first ball drawn is white and if it is not replaced in the bag, then there are 4 white balls and 8 black balls. Therefore, the probability of
drawing a white ball in the second draw = . |
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| In this case, the probability of drawing a white ball in the 2nd draw depends on the occurrence and non-occurrence of the event in the first draw. |
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| Events are said to be independent if the occurrence of one event does not affect the occurrence of others. |
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| Observe in case(a) of above example, |
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| The probability of getting a white ball in the second draw does not depend on the occurrence of the event on the first draw. |
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| However in case(b), the probability of getting a white ball in the second draw depends on the occurrence and non - occurrence of the event in the first draw. |
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| It can be verified by different example. |
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| If A and B are two independent events, then |
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| This is known as Multiplication Rule of Probability. |
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| The converse is also true, that is if two events A and B associated with a random experiment are such that |
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| then the two events are independent. |
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| Two events are said to be dependent if the occurrence of one affects the occurrence of the other. In this case, |
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| In the above example, |
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| let |
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| A = event that the outcome is a white ball in the first draw |
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| B = event that the out come is a white ball in the second draw |
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| In case (a), |
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| \ The probability that both the balls drawn is white |
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| In case (b), |
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| (Since the ball after the first draw is not replaced) |
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| P(B) = P (first draw is white and second draw is white) |
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| + P (first draw is black and second draw is white) |
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(both the balls are white) |
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Here P(A B) P (A). P(B) since the events are not independent. |
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| Two random experiments are said to be independent if for every pair of events E and F, where E is associated with the first experiment and F is associated with the second experiment, the probability of simultaneous occurrence of E and F, when the two experiments are performed, is the product of the probabilities P(E) and P(F), calculated separately on the basis of the two experiments. |
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i.e,. P(E F)= P(E).P(F) |
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| Example: |
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Probability of solving a specific problem independently by A and B are
respectively. If both try to solve the problem independently, find the probability that the problems be solved. |
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| Suggested answer: |
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| Let A be the event of A solving the problem. |
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| Let B be the event of B solving the problem. |
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| Then, |
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| P (A not solving the problem) |
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| P (B not solving the problem) |
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| (Considering the experiments as independent, because A and B solve the problem independently) |
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P (both not solving the problem) |
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Probability that the problem can be solved |
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| Note: |
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| If A and B are independent, then |
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| i) Ac and Bc are independent |
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| ii) Ac and B are independent |
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| iii) A and Bc are independent |
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