Trigonometry (Continued)


   
 
Theorem 2
General solution of cos q = k
 
Method I
 
Let a be the least positive angle such that
 
 
 
 
 
 
 
 
 
Method II
 
Let a be the smaller positive angle with cos a = k.
 
Then, cos(-a) = k
 
cos q = cos a and cos (-a)
 
A = q or - a
 
Also, any co-terminal angle with above is trigonometrically equivalent and so has the same cosine.
 
 
 
q = (Any even multiple of p)+ a or (Any even multiple of p) - a
 
 
Particular Cases
 
 
 
ii) If cos q = 1, then cos a = 1, a = 0
 
 
 
= even multiple of p
 
 
 
= odd multiple of p
 
 
     
   
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