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| R.D and Archimedes' Principle |
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R.D =  |
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| Since weight is proportional to mass |
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R.D  |
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| When a body is immersed in water, it displaces its own volume of water. Upthrust on the body is equal to the weight of this displaced volume of water, which is also equal to loss of weight of the body. Hence 'weight of equal volume of water' can be replaced by upthrust or loss of weight in water. |
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R.D  |
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or R.D  |
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| A solid weighs 50 gf in air and 44 gf when completely immersed in water. Calculate (i) R.D of the solid (ii) upthrust (iii) density of the solid in cgs and SI units. |
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(i) R.D  |
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| = 8.33 |
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| (ii) upthrust = loss of weight = 6 gf |
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| (iii) density in cgs unit 8.33 g cm-3 |
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| In SI unit 8.33 x 103 kg m-3 |
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| When a solid body is immersed in a liquid and then in water, the volume of displaced liquid is the same as the volume of displaced water which is equal to the volume of the solid. |
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R.D of liquid  |
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| Since the volume of displaced liquid = Volume of displaced water, |
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R.D of liquid  |
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| 1. A body weighs 20gf in air, 18.2 gf in a liquid and 18.0 gf in water. Calculate (i) the relative density of the body (ii) and relative density of the liquid. |
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(i) R.D of the solid  |
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| = 10 |
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(ii) R.D of liquid  |
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| = 0.9 |
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| 2. A solid weighs 32 gf in air and 28.8 gf in water. Find how much will it weigh in a liquid of R.D 0.9. |
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R.D of liquid  |
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0.9  |
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| 0.9 x 3.2 = x |
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| x = 2.88 gf |
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| Weight of solid in liquid = 32 - 2.88 = 29.12 gf |
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| Find the weight (W1 gf) of a solid in air using a hydrostatic balance as shown in figure below. |
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| Weighing a solid in air and water |
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| Tie the solid firmly with a thread and suspend it from the hook as shown in figure. Lower the solid in water as shown and find its weight (W2 gf). |
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| Record the result as shown below: |
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| Weight of the solid in air: W1 gf |
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| Weight of the solid in water = W2 gf |
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| Apparent loss of weight of solid = (W1 - W2) gf |
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| Select a solid (sinker) which is insoluble in the given liquid. Weigh the sinker in air. Weigh the sinker in water and finally weigh the sinker in the given liquid. |
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| Determination of the R.D. of a liquid |
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| Record the observations as shown below: |
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| Weight of the sinker in air = W1 gf |
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| Weight of the sinker in water = W2 gf |
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| Weight of the sinker in liquid = W3 gf |
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| Loss of weight of the sinker in water = (W1 - W2) gf |
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| Loss of weight of the sinker in liquid = (W1 - W3) gf |
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| Since volumes of the liquid and water displaced by the sinker are the same and the apparent loss is equal to the mass of the liquid displaced, the above formula can be stated as under: |
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| Relative density of solids like wax, cork etc. is determined by the following method. |
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| Choose a sinker and find its weight in water by suspending it in water as shown in figure (a) below. |
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| Tie the solid cork to the string attached to the sinker and find its weight in air but sinker in water as shown in figure (b) below. |
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| Remove the cork and tie it together with the sinker and suspend it in water as shown in figure (c) and find the weight of the cork together with the sinker in water. |
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| Measuring the relative density of a cork |
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| Record your observations as shown below: |
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| Weight of sinker in water = x gf |
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| Weight of sinker in water + cork in air = y gf |
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| Weight of cork in air = (y - x) gf |
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| Weight of cork + sinker in water = z gf |
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| Upthrust on cork in water = (y - z) gf |
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| The upthrust on cork in water also represents the weight of the water displaced by the cork. Hence, relative density of cork |
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| Following observations are taken while finding the R.D of cork. |
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| Weight of sinker in water = 12.6 gf |
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| Weight of sinker in water + cork in air = 13.7 gf |
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| Weight of sinker and cork, both in water = 10.5 gf |
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| Find the R.D and density of cork. |
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| Weight of cork in air = 13.7 - 12.6 |
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| = 1.1 gf |
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| Weight of cork in water = 10.5 - 12.6 |
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| = -2.1 gf |
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| Since cork floats in water, upthrust on it is more than its own weight as it is made to sink with the force of the sinker, hence weight of cork in water is -ve. |
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R.D of cork  |
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| = 0.33 |
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| density = 0.33 g cm-3 |
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