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| Distance as Area under Velocity-Time Graph |
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| The velocity-time graph for uniformly accelerated motion of a particle is illustrated in the figure. Any two points A, B are chosen on the velocity-time graph from which perpendiculars AC, BD, AE, BF are dropped on the time and velocity axes respectively. The coordinates of the points A and B are [t, v(t)] and [tl, v(tl)] respectively. |
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| Area included under the position of the AB and the time-axis |
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| = area of ACDB = area of rectangle ACDK + area of triangle AKB |
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area ACDB = x (tl) - x (t) which is the distance covered in the time interval (tl - t) |
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| The above relationship has been derived by assuming all the variables v(t), v(tl) and 'a' to be positive. However, the same result can be obtained if any or all of the variables are negative. |
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