 |
| The Electric Potential Energy |
|
| The electric potential energy of the alpha particle at the distance of closest approach from the nucleus was found to be equal to |
| |
| Potential energy x charge on a particle |
| |
 |
| |
 |
| |
| |
| |
| Where Z is the atomic number of the Gold foil, |
| |
| K = 9x109 Nm2/C2 |
| |
| +e = the charge on a proton |
| |
| At r = r0 K.E. of particle = P.E. of a particle |
| |
 |
| |
 |
| |
| Kinetic energy of a particle |
| |
| On substituting the value of |
| |
| (K.E)a = 5.5 Mev |
| |
| = 5.5 x 1.6 x 10 13 |
| |
| Z = 79, e = 16 x 10-19C |
| |
| Value of ro = 4.13 x 10-14 m |
| |
| = 41.3 x 10 -13 m |
| |
| = 41.3 Fermi (1 fermi = 10-13 m) |
| |
| This was approximate radius of the gold nucleus. |
| |
