Atoms and Nuclei


   
 
Numerical 05
05. The second member of Lyman series in hydrogen spectrum has
 
 
Suggested solution:
 
 
For Lyman series, n1 = 1 and n2 = 2,3,4 …..
 
Let l1 and l2 be the wavelengths of the first and second lines respectively.
 
 
 
Dividing,
 
 
 
 
     
   
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