Voltmeter and Ammeter
These devices measure the voltage and current respectively in a circuit. The basic component of both is the moving coil galvanometer which produces a deflection proportional to the electric current through it.Ammeter
An ammeter is connected in series with the circuit element whose current is to be measured, so that there is only a negligible change in the circuit resistance and hence circuit current.Let the galvanometer resistance be G and the current for full-scale deflection be Ig. To measure larger currents, a suitable low resistance S (called shunt) is connected in parallel with the galvanometer.
The value of S is chosen by the maximum current I that we want to measure. This means that though the circuit current is I, only a current Ig should be through the galvanometer. The remaining current
I - Ig = Is should flow through the shunt. Equating potential differences across the shunt and galvanometer, we get(I - Ig) S = Ig G
The resistance of the ammeter (i.e., shunted galvanometer) is
\ RA < S
So, the shunt not only extends the range of current (from Ig to I), it extends the range of current (from G to RA) of the ammeter.Voltmeter
A voltmeter is connected in parallel with the circuit element across which potential difference is to be measured. It should have a very high resistance as not to alter the circuit resistance, and hence circuit current.The galvanometer can measure voltages upto IGG. For larger potential differences, a suitable high resistance R (called multiplier) is connected in series.
The value of R is chosen according to the maximum voltage V that we want to measure. But the galvanometer by itself can only handle a voltage of IgG. The remaining potential difference (V - IgG) should be across the multiplier R. The current through it is Ig. Therefore, equating voltage drops, we get
V = Ig G + Ig R
RV = G + R
Since R is high, the multiplier increases the resistance of the voltmeter, and of course, extends the voltage range (from IgG to V).Wheatstone Bridge
This is used to measure an unknown resistance accurately. It consists of 4 resistors (2 fixed known resistances P and Q, a known variable resistance R and the unknown resistance X) connected as shown in the figure.Wheatstone's network
A source of emf is connected across one pair of opposite junctions (A and C), and a galvanometer G across the other opposite pair (B and D). The key K1 is closed first and then K2. The value of R is varied till the galvanometer shows no deflection, i.e., Ig = 0. Then, the bridge is said to be balanced.
The wheatstone bridge principle states that under balanced conditions, the products of the resistances in the opposite arms are equal, i.e.,
Applying the Kirchhoff's law to loop 1, we have
-I1P - IgRg + (I - I1)R = 0 ...(1)Similarly for loop 2, we have
- (I1-Ig)Q +(I - I1+ Ig)X +IgRg = 0 ...(2)(where Rg is the resistance of the galvanometer)
In the balanced condition, putting Ig = 0, we have-I1P + (I - I1)R = 0 …(1)
and -(I1)Q + (I - I1)X = 0 …(2)Simplifying the two equations, we get
I1P = (I-I1)R …(1)I1Q = (I-I1)X …(2)
Dividing the above two equations, we get
Resistor Q is called the standard arm of the bridge, and resistor P and R are called the ratio arms.



