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| Numerical 03 |
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| 03. A circular coil of radius 8.0 cm and 20 turns rotates about its vertical diameter with an angular speed of 50ms-1 in a uniform horizontal magnetic field of magnitude 3.0 x 10-2 T. Obtain the maximum and the average EMF induced in the coil. If the coil forms a closed loop of resistance 10 W, how much power is dissipated as heat? What is the source of this power? |
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| Suggested solution: |
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| Maximum EMF |
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| E0 = NBAw |
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| = 20 x 3 x 10-2 x 3.14 x (8 x 10-2)2 x 50 volt = 0.6 volt |
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| Average EMF for one cycle is zero. |
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| Maximum current, |
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| Power loss |
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| The source of this power is the external agent (motor) which helps the coil rotating against the torque of the induced current. |
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