03.
A circular coil of radius 8.0 cm and 20 turns rotates about its vertical diameter with an angular speed of 50ms-1 in a uniform horizontal magnetic field of magnitude 3.0 x 10-2 T. Obtain the maximum and the average EMF induced in the coil. If the coil forms a closed loop of resistance 10 W, how much power is dissipated as heat? What is the source of this power?
Suggested solution:
Maximum EMF
E0 = NBAw= 20 x 3 x 10-2 x 3.14 x (8 x 10-2)2 x 50 volt = 0.6 volt
Average EMF for one cycle is zero.Maximum current,
Power loss
The source of this power is the external agent (motor) which helps the coil rotating against the torque of the induced current.
