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| Numerical - 02 |
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| 02. A bar magnet of magnetic moment 1.5 lies aligned with the direction of a uniform magnetic field of 0.22 tesla. |
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| (a) What is the amount of work required to turn the magnet so as to align its magnetic moment. |
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| (i) Normal to the field direction. |
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| (ii) Opposite to the field direction. |
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| What is the torque on the magnet in cases (i) and (ii)? |
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| Suggested solution: |
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| (a) (i) Work required to turn the magnet normal to the field direction. |
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| = MB = 1.5 x 0.22 J = 0.33 J |
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| (ii) Work required to turn the magnet opposite to the field direction |
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| = 2MB = 2 x 0.33 J = 0.66 J |
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