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| Numerical 08 |
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| 08. In the Bohr model of the hydrogen atom the electron revolves around the nucleus in a path of radius 5.1 x 10-11 m at a frequency of 6.8 x 1015 revolution per second. What is the value of magnetic field at the center of the orbit? |
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| Suggested solution: |
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| The electron revolving around the nucleus in a circular orbit is equivalent to a circular conductor carrying current. The current I, by definition |
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| I = Charge / Time = eV |
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| = 1.6 x 10-19 x 6.8 x 1015A = 1.1 x 10-3A |
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| The magnetic field B at the center of circular conductor is |
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| B = monI/2 R |
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| = (4 x 10-7 x 1.1 x 10-3) / (2 x 5.1 x 10-11) = 14 T |
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Moving Charges and Magnetism
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