08.
In the Bohr model of the hydrogen atom the electron revolves around the nucleus in a path of radius 5.1 x 10-11 m at a frequency of 6.8 x 1015 revolution per second. What is the value of magnetic field at the center of the orbit?
Suggested solution:
The electron revolving around the nucleus in a circular orbit is equivalent to a circular conductor carrying current. The current I, by definition
I = Charge / Time = eV= 1.6 x 10-19 x 6.8 x 1015A = 1.1 x 10-3A
The magnetic field B at the center of circular conductor isB = monI/2 R
= (4 x 10-7 x 1.1 x 10-3) / (2 x 5.1 x 10-11) = 14 T