20.
In Young's double slit experiment, the intensity at a point is 75% of maximum intensity. What is the smallest distance of this point from the central fringe? Given d = 0.1mm, D = 1m and l = 600 nm.
Suggested solution:
The intensity I at a point on the screen where the two disturbances arrive having a phase difference s is
I = 0.751max Therefore,

Then,


