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| Numerical - 03 |
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| 03. A small pin fixed on a table top is viewed from above from a distance of 50 cm. By what distance would the pin appear to be raised if it is viewed from the same point through a 15 cm thick glass slab held parallel to the table? Refractive index of glass = 1.5. Does the answer depend on the location of the slab? |
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| Suggested solution: |
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| If y is the distance through which the pin would appear to be raised, then y = Real thickness (of slab) - Apparent thickness (of slab) |
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| or |
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| where m is the refraction index of the material of the slab. |
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| The location of the slab will not affect the answer in any way. |
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