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| Numerical 02 |
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| 02. Six lead-acid type of secondary cells, each of emf 20 V and internal resistance 0.015W, are joined in series to provide a supply to a resistance of 8.5W. Determine (i) the current drawn from the supply and (ii) it's voltage. |
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| Suggested solution: |
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| emf of series combination of cells = 6 x 2 V = 12 V |
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| Total internal resistance of series combination = 6 x 0.015 W = 0.09 W |
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| Total resistance of circuit = (8.5 + 0.09) ohm = 8.59 ohm |
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| Terminal potential difference |
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