Electricity


   
 
Question (1): What is the SI unit of charge?
Answer:  The SI unit of charge is coulomb.
Question (2): How many electrons constitute a charge equal to 1 C?
Answer:  1 Coulomb of charge has 6.25 x 1018electrons.
Question (3): State ohm's law.
Answer:  When temperature and other physical parameters remain constant, the current flowing through a conductor is directly proportional to the potential difference across its ends.
Question (4): Which effect of current is used in the following appliance? a) electric bulb b) immersion rod c) electric iron d) galvanometer
Answer:  For electric bulb, immersion rod and electric iron, heating effect of current is used. For galvanometer magnetic effect of current is used.
Question (5): Define watt and watt hour.
Answer:  Watt is the unit of power. If 1 joule of energy is consumed in 1 second, we say the power of the device is 1 watt. Watt hour is the unit of energy. If a device with a power 1 watt works for 1 hour 1 watt hour amount of energy is consumed.
Question (6): Which of the following graphs depict ohm's law.
Answer: 
image

Graph (a) represents ohm's law since a straight line which shows that 'I' is directly proportional to 'V' (i.e., ohm's law).
Question (7): Two coils have a combined resistance of 25 when connected in series and a resistance of 4 when connected in parallel. What is the resistance of each coil?
Answer:  Let the resistance be R 1 and R 2 , and R s represents resistances in series and R p represents resistance in parallel.
According to the given data

R 1 +R 2 =R S =25 image _______( 1)


image + image = image = image


image_______( 2)

R 1 + R 2 = 25

R 1 R 2 = 100

(R 1 - R 2 ) 2 = (R 1 + R 2 ) 2 - 4 R 1 R2

= 25 2 - 4 (100)

= 625 - 400

= 225

R 1 - R 2 = 15

R 1 + R 2 = 25

Adding 2R 1 = 40

R 1 = 20 R 2 = 5
Question (8): On what factor's does the heating effect of current depend on.
Answer:  The heating effect of current depends on
  • The square of the amount of current flowing
  • The resistance of the wire and
  • The time of flow of current
Question (9): Name the instrument that measures the potential difference across the ends of a current carrying conductor. How is the instrument connected to the circuit?
Answer:  Voltmeter measures the potential difference across the ends of a conductor. It is connected in parallel across the element through which current flows due to a certain potential difference.
Question (10): When are several resistors in a circuit said to be connected in parallel?
Answer:  Several resistors are said to be connected in parallel when the potential difference across the resistors remain the same.
Question (11): Two bulbs have ratings 100 W, 220 V and 60 W, 220 V respectively. Which one has a greater resistance?
Answer:  P=VI=
image For the same V, R is inversely proportional to P. Therefore, the bulb 60 W, 220 V has a greater resistance.
Question (12): A torch bulb has a resistance of
imagewhen cold. It draws a current of 0.2 A from a source of 2 V and glows. Calculate

(i) the resistance of the bulb when glowing and

(ii) explain the reason for the difference in resistance.

Answer:  (i) When the bulb glows:

V = I R ---- Ohm's law
image




image


image

(ii) Resistance of the filament of the bulb increases with increase in temperature. Hence when it glows its resistances is greater than when it is cold.
Question (13): Calculate the resistance of 1 km long copper wire of radius 1 mm. (Resistivity of copper = 1.72 x 10-8
imagem)
Answer:  L = 1 km = 1000 m

R = 1 mm = 1 x 10-3 m


image


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image
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Question (14): When a potential difference of 2 V is applied across the ends of a wire of 5 m length, a current of 1A is found to flow through it. Calculate: (i) the resistance per unit length of the wire (ii) the resistance of 2 m length of this wire (iii) the resistance across the ends of the wire if it is doubled on itself.
Answer:  (i) V = I R ----- Ohm's law
image
image
image
image


(ii) Resistance of 2 m length of the wire = 0.4 x 2
image

(iii) When the wire is doubled on itself:

(1) the area of cross-section is doubled. If A is the original C.S. area, now it is 2 A.

(2) The length becomes half i.e. image

image

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