"3 divided by 3" Introduction
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Divide: 3,192 ÷ 3
Divide: 3,192 ÷ 3 => 1,064 or 64 or 264 or 1000 R192..
Find: 3.456 ÷ 3
Find: 3.456 ÷ 3 => 3 or 6 or 1.152 or 3.456..
Evaluate: (4 × 33) + (12 ÷ 4) × (3) - 3 + 5
Evaluate: (4 × 3 3 ) + (12 ÷ 4) × (3) - 3 + 5 => 131 or 119 or 123 or 127..
6 ÷ 2 = 3. What would happen to the quotient when 6 is divided ..
6 ÷ 2 = 3. What would happen to the quotient when 6 is divided by 3? => The quotient remains the same. or The quotient would decrease. or It cannot be divided. or The quotient would increase...
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Question : SHow all work please!
Answer : 4^2=16 (4+5^2) u do 5^2 first which is 25 then add 4 which is 29 so u now have 16-3*29/3 3*29=87 so now u have 16-87/3 so now u do 87/3=29 then 16-29=(-)13 so ur answer should be -13 Hope i did this all correct its easier when i can see the problem on paper and i know what it is saying Just remember PEMDAS P- Parentesis E- Exponents M- Multiply D- Divide A- Addition S- Subtraction that is the order of operations
Answer : 4^2=16 (4+5^2) u do 5^2 first which is 25 then add 4 which is 29 so u now have 16-3*29/3 3*29=87 so now u have 16-87/3 so now u do 87/3=29 then 16-29=(-)13 so ur answer should be -13 Hope i did this all correct its easier when i can see the problem on paper and i know what it is saying Just remember PEMDAS P- Parentesis E- Exponents M- Multiply D- Divide A- Addition S- Subtraction that is the order of operations
Question : This is a precalculas problem I have and I can't get the right answer.
Answer : First simplify the multiplication: (x+3)(x-3)(x-3)(x-4) =(x^2-9)(x^2-7x+12) =x^4-7x^3+12x^2-9x^2+63x-108 =x^4-7x^3+3x^2+63x-108 Now that, divided by x is: x^3-7x^2+3x+63-108x^-1 = x^3-7x^2+63-108x^-1 Move the 63 from the left to the right side, and your equation comes out to be: x^3-7x^2-108x^-1 is greater than or equal to -63
Answer : First simplify the multiplication: (x+3)(x-3)(x-3)(x-4) =(x^2-9)(x^2-7x+12) =x^4-7x^3+12x^2-9x^2+63x-108 =x^4-7x^3+3x^2+63x-108 Now that, divided by x is: x^3-7x^2+3x+63-108x^-1 = x^3-7x^2+63-108x^-1 Move the 63 from the left to the right side, and your equation comes out to be: x^3-7x^2-108x^-1 is greater than or equal to -63
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