Composite function
Let f : A g B and g : B g C be two functions. Let h: A g C be function such that h(x) = g(f(x)) h is called the composite of f and g, denoted by h = g o f. i.e., (g o f) (x) = g (f(x..
Let f : A g B and g : B g C be two functions. Let h: A g C be function such that h(x) = g(f(x)) h is called the composite of f and g, denoted by h = g o f. i.e., (g o f) (x) = g (f(x..Composition of functions -gof fog
Composition of two functions or Product of two functions - Let f:AgB and g:AgB be two functions. Thus the composition of two functions f and g denoted by gof or fog is the function from A into C defined by gof = {(a,b) for some c..
Composition of two functions or Product of two functions - Let f:AgB and g:AgB be two functions. Thus the composition of two functions f and g denoted by gof or fog is the function from A into C defined by gof = {(a,b) for some c.. Math a30 Functions and compsition of functions
College Algebra with Professor Richard Delaware - UMKC VSI - Lecture 13. In this Lecture,we learn the Algebra of functions.
Question : How is a composition of any f(x) function (trig., log, polynomial) with a linear function (in the form g(x) = A(x + B) affected by the A and B ... in terms of the transformation to f(x). In other words, how does the A and B transform f(x) to f(g(x)) and g(f(x))?
For example, the value of A will cause a vertical stretch/compression by a factor of A in g(f(x)).
Answer : Lesson: given a graph of f(x) how do you graph g(x) = a f(b[x+c]) + d.....1st: f(x) -----> f(x + c) by moving the graph -c units along x axis------> f(b[x+c]) by compressing about x = -c if 1<|b| and expansion if 0<|b|<1.{note if b<0 then first a reflection about x = -c } ---->a f(b[x+c]) is an expansion parallel to y axis if 1<|a| while a compression if 0<|a|<1 {note: if a<0 then first a refection about y = 0 }----> a f(b[x+c]) + d is movement of d units parallel to the y axis... More from Yahoo Answers
Answer : Lesson: given a graph of f(x) how do you graph g(x) = a f(b[x+c]) + d.....1st: f(x) -----> f(x + c) by moving the graph -c units along x axis------> f(b[x+c]) by compressing about x = -c if 1<|b| and expansion if 0<|b|<1.{note if b<0 then first a reflection about x = -c } ---->a f(b[x+c]) is an expansion parallel to y axis if 1<|a| while a compression if 0<|a|<1 {note: if a<0 then first a refection about y = 0 }----> a f(b[x+c]) + d is movement of d units parallel to the y axis... More from Yahoo Answers
Question : I have a function y=2x-9 and I need to know how to get its inverse and then plug those two equations into something like this f(g(x)), how do i do this?
Answer : For the inverse you replace x with y, and replace y with x. So you have... y=2x-9 then you replace... x=2y-9 solve for y move the 9 x+9=2y divide by 2 (x+9)/2=y y= x/2 + 9/2 now it will be function of x will be the graph f(x)=x/2 + 9/2.. More from Yahoo Answers
Answer : For the inverse you replace x with y, and replace y with x. So you have... y=2x-9 then you replace... x=2y-9 solve for y move the 9 x+9=2y divide by 2 (x+9)/2=y y= x/2 + 9/2 now it will be function of x will be the graph f(x)=x/2 + 9/2.. More from Yahoo Answers
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