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Wikipedia
derivative quotient rule : In calculus, the quotient rule is a method of finding the derivative of a function that is the quotient of two other functions for which derivatives exist . ..... More from Wikipedia
Quotient Rule for Differentiation
Quotient Rule for Differentiation - In this section, we derive the formulaIn this section, we derive the formula and use it to differentiate quotients of function..
Quotient Rule for Differentiation - In this section, we derive the formulaIn this section, we derive the formula and use it to differentiate quotients of function..Working Rules to find derivatives
Derivability implies continuity Derivative of a constant function is zero. ..
Derivability implies continuity Derivative of a constant function is zero. .. The Quotient Rule for finding Derivatives - A few basic examples. For more free math videos, visit JustMathTutoring.com - Most of the videos are longer and more in depth as they are not subject to YouTube's 10 minute time constraint! I have organized links to over 100 FREE math videos made by me!
Derivatives - Quotient and Chain Rule and Simplifying - One complete example. For more free math videos, visit JustMathTutoring.com
Question : the directions is just to find the derivative. i just figured both of those rules needed to be used to find the answer.
1/Sqroot(1-x^2)
Can you go by it step by step? How did you know what rule to use first? quotient rule? or chain rule bottom first? thanks!
Answer : I would use the power rule and chain rule. Think of your function as (1-x^2)^(-1/2) Using the power rule and chain rule, then, gives you: (-1/2)(1-x^2)^(-3/2) (-2x) = - x(1-x^2)^(-3/2). First, you bring down the power, then multiply by your function with the power reduced by one. Since there is a function being raised to a power instead of x, you then need to multiply by the derivative of the function.. More from Yahoo Answers
Answer : I would use the power rule and chain rule. Think of your function as (1-x^2)^(-1/2) Using the power rule and chain rule, then, gives you: (-1/2)(1-x^2)^(-3/2) (-2x) = - x(1-x^2)^(-3/2). First, you bring down the power, then multiply by your function with the power reduced by one. Since there is a function being raised to a power instead of x, you then need to multiply by the derivative of the function.. More from Yahoo Answers
Question : The quotient rule states that:
f(x+dx) - f(x) / dx
If I wanted to calculate the derivative of say f(x) = x^2, I know I could use the power rule and get 2x, but something is confusing me using the quotient rule.
My question is: how come the next step is this
(x+dx)^2 - x^2
I guess its because I never dealt with a function like: f(x+y) where 'y' is some other term.
Consider just f(x+dx), where:
f(x) = 2
f(x)=2x
f(x)=z^3
Can someone answer those 3?
Thanks.
Note* I can easily see the secon..
Answer : I have never seen the quotient rule stated like that. Normally it looks like this: If y=f/g, then y' = (f'g - fg') / g^2 So for y = x^2, for instance y = (x^2)/1 f = x^2 g = 1 y' = (2x - 0) / (1^2) = 2x But as you stated, you could use the power rule much easier for that problem... More from Yahoo Answers
Answer : I have never seen the quotient rule stated like that. Normally it looks like this: If y=f/g, then y' = (f'g - fg') / g^2 So for y = x^2, for instance y = (x^2)/1 f = x^2 g = 1 y' = (2x - 0) / (1^2) = 2x But as you stated, you could use the power rule much easier for that problem... More from Yahoo Answers