finding the general term

  I use Wordtracker to find niche keyphrases, this example shows how you can start off with a very general term like 'Christmas' and find keyphrases that very few sites are optimized for, but lots of people search for. This makes the SEO real easy.

  an appointed festival, 2) the seventh year of a seven year cycle, 3) the Jubilee year (50th year at the end of a 49 year cycle). The general term "Sabbath" meant a God-designated time of rest, a cessation of regular work. Secondly, in the Bible, a day was considered as extending from evening to evening. This was instituted at Creation. In the Genesis account, we find the terms "And there was evening, and there was morning, the (first, second, third, etc.) day." (See Genesis chapter 1). Gen ...

Question : in the sequence i cant find the general term i dont get it. i dont get how do they know if you have to have an exponent and stuff. please help me. like for example this 1,-2,3,-4 ( ive got the answers but i just dont get how they got it :| the answer is Asubn= -1^n+1(negative one to the n+1 power?)then multiplied by n. i really dont get how they do that please help. any tips or ANYTHING:)

Answer : Every time you multiply -1 by itself (exponent), it simply reverses its sign. Example: -1 ^ 1 = -1 -1 ^ 2 = 1 -1 ^ 3 = -1 -1 ^ 4 = 1 -1 ^ 5 = -1 ... In your series (1, -2, 3, -4) every term reverses its sign alternatively. You can use the property of -1^n shown above to solve that term. Multiply [-1^(n+1)] (which will come out to 1, -1, -1, 1) by the number of the term (1, 2, 3, or 4) to get your series -1^(n+1)*n = (1,-2,3,-4)..   More from Yahoo Answers

Question : I have several questions like this but if you can show me how to figure the general term for this one so I can get an idea of how to do it, that would be great, and if you're first to do so you're guaranteed best answer! George entered a function into his calculator and found the following partial sums: s1=0.0016, s2=0.0096, s3=0.0496, s4=0.2496,s5=1.2496. Determine the general term of the corresponding sequence.

Answer : It's just down to observation really, there's no general method. In the case of the one you've given, s1=(20-4)/10000 s2=(100-4)/10000 s3=(500-4)/10000 s4=(2500-4)/10000 s5=(12500-4)/10000 ... sn=(5^(n-1).20 -4)/10000 I wish I could tell you there's a magical method behind it, but I got that just by a lucky observation...   More from Yahoo Answers