"How to solve algebraic solutions" Introduction
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Algebra solving solution problems:
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Question : I need help solving these problems!
It says to use graph to estimate solutions...
1. 2x squared plus 4x equals 6
And this one says to solve algebraically..
1. 2x squared = 32
2. 4x squared = 100
3. 4x squared = 6
4. x squared -11 = 14
5. x squared - 15 = 36
Please and Thank you!
Answer : divide the answer by the coefficent & sqare root ex: (2)x squared = 32 2/32 = 16 & squar root it answer : 4
Answer : divide the answer by the coefficent & sqare root ex: (2)x squared = 32 2/32 = 16 & squar root it answer : 4
Question : it's linear algebra.find value, x y, z, (one dimensional)
-2x+5y-7z=4
4x-10y+14z=-8
-6x+15y-21z=12
(2 parameters)
Answer : that system contains redundancy - the third equation is simple 3 times the first, so you could ignore it, its not telling you anything new. also, the second equation is -2 times the first, so again theres redundant information in teh system. the system may be represented then by one equation, the first one, which is:- -2x + 5y - 7z = 4 the solution will be parametric, so letting y = s, and z = t, then we can solve for 'x' as:- -2x + 5s - 7t = 4 -2x = 4 - 5s + 7t x = -2 + 5/2 s - 7/2 t so, the parametric solution is:- x = -2 + 5/2 s - 7/2 t y = s z = t
Answer : that system contains redundancy - the third equation is simple 3 times the first, so you could ignore it, its not telling you anything new. also, the second equation is -2 times the first, so again theres redundant information in teh system. the system may be represented then by one equation, the first one, which is:- -2x + 5y - 7z = 4 the solution will be parametric, so letting y = s, and z = t, then we can solve for 'x' as:- -2x + 5s - 7t = 4 -2x = 4 - 5s + 7t x = -2 + 5/2 s - 7/2 t so, the parametric solution is:- x = -2 + 5/2 s - 7/2 t y = s z = t
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