How To Solve Extraneous Solutions





"How to solve extraneous solutions" Introduction


From   Wikipedia , TutorVista
Wikipedia
Extraneous and missing solutions - Wikipedia, the free encyclopedia - By analogy, we might suppose we can solve the following equation by subtracting 2 x ... The valid solution x = 2 is gone, and the extraneous solution x = 2 has appeared...

TutorVista
Example to solve extraneous solution:
Example: solve the equation x+13=0 and check whether the solution is extraneous or not. Given: x+13=0 x = -13 Squ..
Solve extraneous solution:
Extraneous solution-multiplication: The fundamental rule of algebra is that we can multiply both the sides of an equation by the related expression without changing ..
Steps to find the extraneous solutions:
First simplify the equation and solve for the variable. Then substitute back the solutions in the original equation. Verify whether the solution satisfy the..
extraneous solutions to radical equations
the principal root another way to do it me rewrite the original equation let me rewrite the original equation we had the square root of X. is equal to 2X -6 now we set for is a solution to ..

"How to solve extraneous solutions" Videos


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  solve system by elimination method, how many solutions   solve system by elimination method, how many solutions

"How to solve extraneous solutions" Questions & Answers


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Question : Employees of a discount appliance store receive an additional 20% off of the lowest price on an item. If an employee purchases a dishwasher during a 15% off sale, how much will he pay if the dishwasher originally cost $450?

Answer : I believe I need to have 1 more question to answer, as the additional discount can be added with the 15% off on the lowest price, or the additional discount is applied after the 15% is off from the lowest price. I'll illustrate how the 2 methods of calculation will come up with 2 different net prices. 1) discount rate: 15%+20%=35% off. 450 - (450x35%) = 450 - 157.5 = 292.5 (net price) 2) discount rate: first 15%, then 20% 450 - (450x15%) = 450 - 67.5 = 382.5 382.5 - (382.5x20%) = 382.5 - 76.5 = 306 (net price)

Question : how to solve a problem like: x+3(x+4)=20. what are the steps to solve this problem?

Answer : You need to distribute.... X+3(X+4)=20 X + 3X + 12 = 20 //distributed 3 among what is in the parenthesize 4X + 12 = 20 //simplify 4X = 8 //subtract 12 X = 2 //simplify My YouTube: http://www.youtube.com/FilmingHumor/