n dimensional vectors





"N dimensional vectors" Introduction


From   Wikipedia , TutorVista
Wikipedia
n-dimensional space - Wikipedia, the free encyclopedia - This is a 4 4 matrix that represents rotation at two speeds at once: See also. coordinate space; n-dimensional calculus; facet (mathematics) fourth dimension; four-vector..

N-dimensional space - In mathematics, an n-dimensional space is a topological space whose dimension is n (where n is a fixed natural number). The archetypical example is n-dimensional Euclidean space, which describes Euclidean geometry in n dimensions. n-dimensional spaces with large values of..

TutorVista
Which solid can be represented as a three dimensional picture using th..
Which solid can be represented as a three dimensional picture using the figure and vector? => pyramid or sphere or cylinder or circle..
Position vector
two dimension position vector . In addition to this, the direction of the position vector gives the direction q in which P lies, as observed from 0. It is important to note that position vectors are different for different positions of the particle. The above explanation can be extended to a three dimen..
The figure M'N'O'P' is the image of MNOP. Describe the vector by using..
The figure M'N'O'P' is the image of MNOP. Describe the vector by using ordered pair notation. =><7, 7> or <- 3, - 7> or <7, 5> or <3, 7>..
Generalisation to N - Particles
>According to Newton's third law, For any a t h particle Substituting a = 1, 2,.. N. We have N equations. Adding them all, The position vector of the centre of mass of the whole system is given by, Where M = m 1 +m 2 +-------m N..

"N dimensional vectors" Questions & Answers


From   Yahoo Answers
Question : Prove that F^(infinity) is infinite dimensional, where F^(infinity) denotes the vector space consisting of all sequences of elements of real or complex numbers.

Answer : Assume that F has dimension n, which is a finite positive integer. Let a1 be the sequence starting with a 1 and all the other terms 0. Let a2 be a sequence of all zeros except the second term, which is 1. ... Let an be a sequence of all zeros except the n-th term, which is 1. Clearly, are linearly independent. Now let's construct a sequence a(n+1) with all terms 0 except the (n+1)st, which is 1. Now, it's impossible to arrive at a(n+1) as a linear combination of , thus, the vector space cannot be n-dimensional for any positive integer n (proof by contradiction). To Theodore: it can be proven that all vectors of an n-dimensional vector space can be written as linear combinations of ANY of the possible bases, so it follows that if a vector cannot be written as a linear combination of some basis then no other basis with n elements works.

Question : How do you resolve three dimensional vectors? Eg. [N 33 degrees E 44 degrees U]

Answer : I assume there is a comma between E and 44 and U means up Let V be the magnitude of the vector. i, j, k are unit vectors in x, y, z directions respectively The vector's projection in the x-y plane is Vcos44 90-33=57 That projection has components Vcos44[cos57 i + sin 57 j ] The projection of the vector on the z-axis is Vsin44 k So adding it up you have V{cos44*cos57 i + cos44*sin57 j + sin44 k }

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