problems on simultaneous equations with three variables


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"Problems on simultaneous equations with three variables" Introduction


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Simultaneous Equations
Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some..
Methods to Solve Simultaneous Equations
Simultaneous Equations - Consider a linear equations in two variables , say, 3x - 2y = 5. It has an infinite number of solutions, some of these are x = 0, Consider a linear equations in two variables , say, 3x - 2y = 5...

"Problems on simultaneous equations with three variables" Videos


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  Homogeneous Linear Systems with Constant Coefficients: Solution via Matrix Eigenvalues (Real and Distinct Case). View the complete course: ocw.mit.edu License: Creative Commons BY-NC-SA More information at ocw.mit.edu More courses at ocw.mit.edu

"Problems on simultaneous equations with three variables" Questions & Answers


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Question : Write a programme, using matrices, to solve simultaneous equations. You need only solve problems with two or three variables; For example: Two variables: 3x + 4y = 2, 7x - 3y = 5. Three variables: x - 2y + 3z = 6, 2x - y + z = 3, 3x + y - 2z = -1.The trick is to input the problem as a matrix problem, and then use the inverse of the matrix to solve it. In C programming language

Answer : #include #include using namespace std; #define rep(i, n) for((i) = 0; (i) < (n); (i)++) #define rep2(i, k, n) for((i) = k; (i) < (n); (i)++) void f21(); int n; double mat[100][100]; int main() { while(true) { cin >> n; if(!n) break; memset(mat, 0, sizeof(mat)); f21(); } return 0; } void f21() { cout << "****************************************" << endl; cout << "* INVERSE OF MATRIX *" << endl; cout << "****************************************" << endl; cout << "ORDER OF THE MATRIX: " << n << endl; cout << "ENTER ELEMENT ROW-WISE" << endl; int m = 2*n; int i, j, k; rep(i, n) { rep(j, n) { cin >> mat[i][j]; cout <<"\t"; printf("%5.3lf", mat[i][j]); } rep2(j, n, m) { if(i == (j-n)){ mat[i][j] = 1; continue; } mat[i][j] = 0; } cout << endl; } cout << endl << "INVERSE MATRIX: " << endl; double pivot, comm; rep(i, n) { pivot = mat[i][i]; if(mat[i][i] == 0){ cout << "DIVISION BY ZERO." <More from Yahoo Answers

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