Substitution Method
Solve the Systems of linear equations by Method of Substitution: 2x - 9y = 0 (i) x - 18y = 27 (ii..
Substitution Method-Simultaneous Equations
Substitution Method - Solve 2x - 9y = 0 (i) x - 18y = 27 (ii) From (i) 2x - 9y = 0 2x = 9y (iii) Substituting this value of x in (ii), we get, 9y - 36y = 54 - 27y = 54 y = -2 Substitute this value of y in (iii): = -..
Substitution Method - Solve 2x - 9y = 0 (i) x - 18y = 27 (ii) From (i) 2x - 9y = 0 2x = 9y (iii) Substituting this value of x in (ii), we get, 9y - 36y = 54 - 27y = 54 y = -2 Substitute this value of y in (iii): = -.. Videos by Julie Harland yourmathgal.com This is part 1 of how to solve a system of equations using the substitution method. The first system solved is 2x - y = -5 and y = x + 4. The second system solved is 3x + y = -14 and 4x + 3y = -22.
Central Wyoming College Gear Up has produced a series of videos to help you prep for the ACT exam. Roger Melton explains test taking strategies.
Question : The question i have that has to be solved by substitution looks like this:
4x + 5y = 48
y = 3x +2
The question i have that has to be solved by linear combination looks like this:
3x - 5y =1
2x + 5y = 9
It would be helpful if u could solve it as well as tell how to...
Thanks
Answer : Linear combination is also called elimination. Check out my eHow article on how to solve a system of two linear equations and two unknowns by using the substitution method: http://www.ehow.com/how_4847206_two-unknowns-using-substitution-method.html Check out my eHow article on how to solve a system of two linear equations and two unknowns by using the elimination (linear combination) method: http://www.ehow.com/how_4847235_two-unknowns-using-elimination-method.html For the first one, you already know y=3x+2. Plug this into the first equation for y to get: 4x+5(3x+2)=48 Solve for x: 4x+15x+10=48 19x+10=48 19x=38 x=2 Now we want to find y. Plug in 2 for x in either equation and solve for y. I'll use the bottom equation, so: y=3(2)+2 y=6+2 y=8 So, x=2, y=8 (answer) For the second problem, add the two equations together since it will result in one of the variables canceling out. You get: 5x=10 Solve for x: x=2 Now plug this x value into either.... More from Yahoo Answers
Answer : Linear combination is also called elimination. Check out my eHow article on how to solve a system of two linear equations and two unknowns by using the substitution method: http://www.ehow.com/how_4847206_two-unknowns-using-substitution-method.html Check out my eHow article on how to solve a system of two linear equations and two unknowns by using the elimination (linear combination) method: http://www.ehow.com/how_4847235_two-unknowns-using-elimination-method.html For the first one, you already know y=3x+2. Plug this into the first equation for y to get: 4x+5(3x+2)=48 Solve for x: 4x+15x+10=48 19x+10=48 19x=38 x=2 Now we want to find y. Plug in 2 for x in either equation and solve for y. I'll use the bottom equation, so: y=3(2)+2 y=6+2 y=8 So, x=2, y=8 (answer) For the second problem, add the two equations together since it will result in one of the variables canceling out. You get: 5x=10 Solve for x: x=2 Now plug this x value into either.... More from Yahoo Answers
Question : Solve by substitution: X^4 - 7X^2 = - 10
I have no clue how to do this.
Answer : X^4 - 7X^2 = - 10 This equation is in 'quadratic' form. You can use u-substitution to solve. Set equal to 0 x^4 - 7x^2 + 10 = 0 let u = x^2 (temporarily) then, u^2 - 7u + 10 = 0 that looks familiar ?! (u - 5)(u - 2) = 0 u = 5 and u = 2 BUT, u = x^2 So, x^2 = 5 x = 5 x^2 = 2 x = 2 QED.. More from Yahoo Answers
Answer : X^4 - 7X^2 = - 10 This equation is in 'quadratic' form. You can use u-substitution to solve. Set equal to 0 x^4 - 7x^2 + 10 = 0 let u = x^2 (temporarily) then, u^2 - 7u + 10 = 0 that looks familiar ?! (u - 5)(u - 2) = 0 u = 5 and u = 2 BUT, u = x^2 So, x^2 = 5 x = 5 x^2 = 2 x = 2 QED.. More from Yahoo Answers
Looking for More Help!
