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Theorem 1
Theorem 1 - Parallelograms on the same base and between the same parallels are equal in area. ABCD and ABEF are two parallelograms on the same base AB and between the same parallels AB, DE area (ABCD) = area (ABEF) An alternate way of proving this theorem is as follows..
Theorem 1 - Parallelograms on the same base and between the same parallels are equal in area. ABCD and ABEF are two parallelograms on the same base AB and between the same parallels AB, DE area (ABCD) = area (ABEF) An alternate way of proving this theorem is as follows..Theorem 1
Theorem 1 - If two sides of a triangle are equal, the angles opposite to them are equal. In AB = AC Draw AD, the bisector of to meet BC at ..
Theorem 1 - If two sides of a triangle are equal, the angles opposite to them are equal. In AB = AC Draw AD, the bisector of to meet BC at .. Introduction to raising (a+b)^n
(Stewart 4.2.16) This video discuss how to use the Mean Value Theorem to solve some problems. The problem is taken from Stewart Calculus book (Early Trancendental 6th ed.) problem 4.2.16
Question : (1+5i)6 ; 1^2=-1
I know that as "1" gets smaller, "i" gets larger.
[[[[[ Answer is: -6624 + 16,280i ]]]]] I meant (1+5i)^6
Answer : Construct the Pascal Triangle: 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 1 6 15 20 15 6 1 Write out the terms: 1*(1^0)(5i)^6 + 6*(1^1)(5i)^5 + 15*(1^2)(5i)^4 + 20*(1^3)(5i)^3 + 15*(1^4)(5i)^2 + 6*(1^5)(5i)^1 + 1*(1^6)(5i)^0 Simplify, noting that i^2=-1, i^3=-i, i^4=+1, i^5=i, i^6=-1: (-15625) + 6*(3125i) + 15*(625) + 20*(-125i) + 15*(-25) + 6*(5i) + 1 = -6624 + 16280i.. More from Yahoo Answers
Answer : Construct the Pascal Triangle: 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 1 6 15 20 15 6 1 Write out the terms: 1*(1^0)(5i)^6 + 6*(1^1)(5i)^5 + 15*(1^2)(5i)^4 + 20*(1^3)(5i)^3 + 15*(1^4)(5i)^2 + 6*(1^5)(5i)^1 + 1*(1^6)(5i)^0 Simplify, noting that i^2=-1, i^3=-i, i^4=+1, i^5=i, i^6=-1: (-15625) + 6*(3125i) + 15*(625) + 20*(-125i) + 15*(-25) + 6*(5i) + 1 = -6624 + 16280i.. More from Yahoo Answers
Question : I need to write my answer in rectangular coordinates and give an exact answer. Thanks so much for your help!
Answer : DeMoivre's Theorem states that (r*cis( ))^n equals (r^n)*cis(n ). Therefore, (1/2 cis 150 degrees)^4 would equal ((1/2)^4)*cis(150*4), or (1/16)cis(600). rcis equals r(cos + i*sin ) in rectangular coordinates so you would do (1/16)cos600 + i((1/16)sin600), which simplifies to -1/32 - (sqrt(3)/32)i... More from Yahoo Answers
Answer : DeMoivre's Theorem states that (r*cis( ))^n equals (r^n)*cis(n ). Therefore, (1/2 cis 150 degrees)^4 would equal ((1/2)^4)*cis(150*4), or (1/16)cis(600). rcis equals r(cos + i*sin ) in rectangular coordinates so you would do (1/16)cos600 + i((1/16)sin600), which simplifies to -1/32 - (sqrt(3)/32)i... More from Yahoo Answers