Wikipedia
what is abscissa? : In mathematics, a Cartesian coordinate system (also called rectangular coordinate system) specifies each point uniquely in a plane by a pair of numerical coordinates, which are the signed distances from the point to two fixed perpendicular directed lines, measured in the same unit of length. Each reference line is called a coordinate axis or just axis of the system, and the point where they meet is its origin. The coordinates can also be defined as the positions of the perpendicular projections of the point onto the two axes, expressed as a signed distances from the origin. One can use the same principle to specify the position of any point in three- dimensional space by three Cartesian coordinates, its signed distances to three mutually perpendicular planes (or, equivalently, by its perpendicular projection onto three mutually perpendicular lines). In general, one can specify a point in spaces of any dimension n by use of n Cartesian coordinates, the.. More from Wikipedia
what is abscissa? : A Cartesian coordinate system specifies each point uniquely in a plane by a pair of numerical coordinates, which are the signed distances from the point to two fixed perpendicular directed lines, measured in the same unit of length. Each reference line is called a coordinate axis or.. More from Wikipedia
Question 3
Question: (a) Plot a point P on the graph paper whose abscissa is 4 and ordinate is 3. (b) Plot a point Q on the graph paper whose abscissa is -3 and ordinate is -2.5. (c) Plot a point R on the graph paper whose abscissa is zero and ordinate is 4. (d) Plot a point..
Question: (a) Plot a point P on the graph paper whose abscissa is 4 and ordinate is 3. (b) Plot a point Q on the graph paper whose abscissa is -3 and ordinate is -2.5. (c) Plot a point R on the graph paper whose abscissa is zero and ordinate is 4. (d) Plot a point..Rectangular co - ordinates
The position of the point P in a plane in the rectangular co-ordinate system is determined as follows: Draw PA and PB perpendicular to XX' and YY'. The segment OA = a measures the distance along the x-axis (the x-coordinate and the perpendicular distance AP = OB = b ( parallel to y - axis) measu..
The position of the point P in a plane in the rectangular co-ordinate system is determined as follows: Draw PA and PB perpendicular to XX' and YY'. The segment OA = a measures the distance along the x-axis (the x-coordinate and the perpendicular distance AP = OB = b ( parallel to y - axis) measu.. . But before we begin I'll draw a straight line on the board. Let me just mark the origin here. Each point on this line can be located by its distance from the origin, with a minus sign, if it is on the left and a plus sign if it is on the right. Usually, the number is denoted by x and is called the abscissa. Since the position of a point on a line can be described by a single number, we say that the line has dimension 1. Now, I draw a second axis, perpendicular to the first one. Each ...
is just a quarter turn. Note that the modulus does not change but the argument increases by 90 degrees. Indeed this is quite a sophisticated way of saying that we just rotated the picture! Well, a bit more complicated... Multiplication by 1+i. Look at the complex number 1+i; it corresponds to the point with abscissa 1 and ordinate 1: its argument is 45 degrees and its modulus is the square root of 2, using Pythagoras' theorem. Hence, a multiplication by 1+i amounts first to multiplying ...
Question : I need to draw a graph. According to the directions, I need to, "supress the origin of the abscissa so that the range of my X values covers the hozrizontal scale" I don't know what this means - that is, what is the origin of the abscissa and how I would "suppress it". Anyone have any ideas? Thanks.
Answer : Abscissa is just a fancy word meaning x-axis. So what its basically say is draw your graph in such a way that you can fit all your x values along the x axis... More from Yahoo Answers
Answer : Abscissa is just a fancy word meaning x-axis. So what its basically say is draw your graph in such a way that you can fit all your x values along the x axis... More from Yahoo Answers
Question : What is the Abscissa of the point on the x-axis that is equidistant from A(-2,3) and B(10,6). Please help me!
Answer : Your question is phrased a little vaguely. You will have to decide whether this answer or the first one given solves the problem you had in mind. The desired point is on the abscissa (y = 0), so its coordinates are (x,0). The distance from point A is (yA - y0) + (xA - x0) and from point B is (yB - y0) + (xB - x0) setting these equal to each other with x0 = x and y0 = 0, [yA + (xA-x) ] = [yB + (xB-x) ] We can drop the square-root signs since we are interested in only the positive roots: yA + (xA-x) = yB + (xB-x) Substituting (-2,3) for (xA,yA) and (10,6) for (xB,yB): 3 + (-2-x) = 6 + (10-x) 9 + 4 + 4x + x = 36 + 100 - 20x + x 13 + 4x = 136 - 20x 24x = 123x x = 123/24 = 5.125 The corresponding distances from A and B are d = [3 + (-2-x) ] = [6 + (10-x) ] d = [3 + (-2-5.125) ] = [6 + (10-5.125) ] d = [9 + (-7.125) ] = [36 + (4.875) ] d = 59.765625 = 59.7656.... More from Yahoo Answers
Answer : Your question is phrased a little vaguely. You will have to decide whether this answer or the first one given solves the problem you had in mind. The desired point is on the abscissa (y = 0), so its coordinates are (x,0). The distance from point A is (yA - y0) + (xA - x0) and from point B is (yB - y0) + (xB - x0) setting these equal to each other with x0 = x and y0 = 0, [yA + (xA-x) ] = [yB + (xB-x) ] We can drop the square-root signs since we are interested in only the positive roots: yA + (xA-x) = yB + (xB-x) Substituting (-2,3) for (xA,yA) and (10,6) for (xB,yB): 3 + (-2-x) = 6 + (10-x) 9 + 4 + 4x + x = 36 + 100 - 20x + x 13 + 4x = 136 - 20x 24x = 123x x = 123/24 = 5.125 The corresponding distances from A and B are d = [3 + (-2-x) ] = [6 + (10-x) ] d = [3 + (-2-5.125) ] = [6 + (10-5.125) ] d = [9 + (-7.125) ] = [36 + (4.875) ] d = 59.765625 = 59.7656.... More from Yahoo Answers
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