Question: A furniture dealer trades in two items, tables and chairs. He invests $60,000 in buying tables and chairs. He has a storage capacity for 600 pieces. A table costs him $120 and a chair $40. He can sell a table for a profit of $10 and a chair for a profit of $6. How should he invest his money in order to make maximum profit? Steps to derive 1 Let the number of tables and chairs to be purchased be x y 2 P = 10x y 3 The dealer can invest $60,000 we have 120x y x y 4 x y 5 x y x y 6 The feasible region determined by the above constraints is shown.7 From the graph the vertices are (0, 0), (500, 0), (450, 150) and (0, 600)8 At (0, 0), P = 10(0) + 6(0) = 09 At (500, 0), P = 10(500) + 6(0) = 500010 At (450, 150), P = 10(450) + 6(150) = 540011 At (0, 600), P = 10(0) + 6(600) = 360012 So, the maximum profit can be obtained by purchasing 450 tables and 150 chairs.Hence the right answer is Option A Click Here To Go Back The distance between place A and place B is 61.7 km. 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