Question: A machine produces bolts, of which 10% are defective. Find the probability that in a random sample of 400 bolts produced by the machine, at the most 30 will be defective. A ) 5.67% B ) 7.65% C ) 6.57% D ) 7.56% Steps to derive 1 The probability for a bolt to be defective, p = 10% = 1 10 , q = 1 - p = 9 10 and n = 400.2 n·p = 400 × 1 10 = 40 > 5n·q = 400 × 9 10 = 360 > 5 So, the use of normal approximation to the binomial distribution is appropriate.3 Mean, μ = n·p = 400 × 1 10 = 404 Standard Deviation, σ = n ⋅ p ⋅ q = 4 0 0 × 1 1 0 × 9 1 0 = 6
5 Write the problem in probability notation: P (x ≤ 30), where x denotes the number of defective bolts chosen at random.6 P (x < 30 + 0.5) = P (x < 30.5) [Rewrite the problem using the continuity correction factors.]7 The corresponding area under the normal curve distribution is shown in the diagram.8 The z value corresponding to x = 30.5 is given by, z = ( x - μ ) σ = ( 3 0 . 5 - 4 0 ) 6 = - 9.5 6 = - 1.5833
9 The area between z = 0 and z = - 1.5833 is 0.4433 by referring to the table for the probability z .10 The area for z ≤ - 1.5833 is 0.5 - 0.4433 = 0.0567.11 So, the probability that at the most 30 bolts will be defective = 5.67%.Hence the right answer is Option A Click Here To Go Back Few Other Questions - In triangle DEF, if ∠E = 54o30', d = 21.4, and f = 10.6, then Find ∠D to the neare.. For any parallelogram, find the ratio of sum of the squares of the lengths of the diagonal.. Find the length of AC to two significant digits in the parallelogram ABCD... Find the area of the parallelogram ABCD to three significant digits... In a quadrilateral ABCD, if AB = 10.6, BC = 14.8, CD = 8.4 and DA = 12.6 and ∠ABC = 70.. A pole is located at a distance of 20 m from one building and 26 m from another. The measu.. ABCDEF is a regular hexagon inscribed in a circle with center O and a radius of 17 cm. Fin.. An equilateral triangle ABC is inscribed in the circle with center 'O' and radius 9 cm. 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