Question: A manufacturer reported that 95% of electronic components manufactured by them are free from defects. From a random sample of 80 components, 5 had defects. Find the p α = 0.01? Steps to derive 1 H0 : p 1 : p 2 Sample proportion, p ˆ 75 80 3 The test value, z p ˆ - p p ( 1 - p ) n p n 4 z 0 . 9 3 7 5 - 0 . 9 5 ( 0 . 9 5 ) ( 0 . 0 5 ) 8 0 5 Area under the standard normal distribution curve for z z 6 P-value for a two tailed test = 2 × P(z 6 = 2(0.5000 - 0.1950) = 0.617 The P-value 0.61 > 0.01, do not reject the null hypothesis.8 So, there is not enough evidence to reject the manufacturer's report that 95% of electronic components have no defects.Hence the right answer is Option D Click Here To Go Back Anna has different colors of ribbons. The lengths of the ribbons are shown in the table.Co.. The table shows the temperatures in four different cities.CityCity - ACity - BCity - CCity.. Barbara filled 10 cups with apple juice. Each cup was filled with 300 milliliters of juice.. 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