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Question: An Opera house collected $17,400 by selling the tickets. The people sitting in the row A are charged $19 and the people sitting in row B are charged $14. The total number of tickets sold is 1,050. Find the number of people sitting in row A and row B.


A ) 540 in row A and 510 in row B
B ) 511 in row A and 539 in row B
C ) 510 in row A and 540 in row B
D ) 539 in row A and 511 in row B

Steps to derive

1 Number of people in row A = x

2 Number of people in row B = y

3 x + y = 1050 --- (1)
 [Express as a linear equation.]

4 19x + 14y = 17400 --- (2)
 [Equation for the money collected by selling tickets.]

 [Rearrange equation 1.]
8 y = 1050 - x

 [Substitute the values.]
9 19x + 14(1050 - x) = 17400

 [Group the like terms.]
10 5x + 14700 = 17400

 [Subtract 14700 from the two sides of the equation.]
11 5x = 2700

 [Divide throughout by 5.]
12 x = 540

 [Substitute the values.]
13 y = 1050 - 540 = 510

14 The number of people sitting in row A are 540 and the number of people sitting in the row B are 510.



Hence the right answer is Option A

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